def is_p(n):
for i in range(2,int(n**0.5)+1):
if n%i == 0:
return i
return True
for i in range(int(input())):
n = int(input())
imp = is_p(n)
if n%2==0:
print(n//2,n//2)
elif imp==True:
print(1,n-1)
else:
x = n//imp
print(x,((n//x-1)*(x)))
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define mod 1000000007;
bool prime(ll x)
{
for(ll i=2;i<=sqrt(x);i++)
{
if(x%i==0) return false;
}
return true;
}
int main()
{
ll t;
cin>>t;
while(t--)
{
ll n;
cin>>n;
if(n%2==0)
{
cout<<n/2<<" "<<n/2<<endl;
}
else if(prime(n)){
cout<<1<<" "<<n-1<<endl;
}
else {
for(int i=2;i<=n-1;i++)
{
if(n%i==0)
{
cout<<(n/i)<<" "<<n-(n/i)<<endl;
break;
}
}
}
}
}
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